1=(3/27)^4x+5

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Solution for 1=(3/27)^4x+5 equation: 



1=(3/27)^4x+5

We move all terms to the left:

1-((3/27)^4x+5)=0



Domain of the equation: 27)^4x+5)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+3/27)^4x+5)+1=0

We multiply all the terms by the denominator


-((+3+1*27)^4x+5)=0



We calculate terms in parentheses: -((+3+1*27)^4x+5), so:

(+3+1*27)^4x+5

We add all the numbers together, and all the variables

30^4x+5

Back to the equation:

-(30^4x+5)



We get rid of parentheses

-30^4x-5=0

We move all terms containing x to the left, all other terms to the right

-30^4x=5

x=5/1

x=5

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